Saturday, January 1, 2011

Product of waking up at 5 PM

42.  What is the solution to the equation  x = 1/raccoon

a)   x = 1/raccoon
      (x)(raccoon) = 1
      d/dx [(x)(raccoon)] = d/dx (1)
      raccoon = 0

7 comments:

  1. Is that what you call Raccoon Calculus?

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  2. This comment has been removed by the author.

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  3. No solution available until either raccoon or x is defined since raccoon cannot equal 0.

    I derped up the last comment really badly.

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  4. Heheh, coming back to this is so hilarious. Twas a funny morning.

    Anyway, happy new years everyone.

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  5. This reminds me of the following:

    1+2+3+4+... = -1/12.

    See e.g. wikipedia's "1 + 2 + 3 + 4 + …" for what that supposed to mean.

    Happy New Year!

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